Simultaneous equations consist of two or more equations that are true at the same time. Consider the following example:
Claire and Laura are sisters; we know that
| (i) | Claire is the elder sister, |
|---|---|
| (ii) | their ages added together give 20 years, |
| (iii) | the difference between their ages is 2 years. |
Let x = Claire's age, in years and y = Laura's age, in years.
| x + y = 20 |
| x - y = 2 |
This is an example of a pair of simultaneous equations.
In this section we consider two methods of solving pairs of simultaneous equations like these.
Use a graph to solve the simultaneous equations:
| x + y | = | 20 |
| x - y | = | 2 |
| x + y | = | 20 |
| y | = | 20 - x |
| x - y | = | 2 | |
| x | = | y + 2 | |
| x - 2 | = | y | |
| or | |||
| y | = | x - 2 |

Use a graph to solve the simultaneous equations:
| x + 2y | = | 18 |
| 3x - y | = | 5 |
| x + 2y | = | 18 | ||
| 2y | = | 18 - x | ||
| y | = | |||
| y | = |
| ||
| y | = |
|
| 3x - y | = | 5 | |
| 3x | = | y + 5 | |
| 3x - 5 | = | y | |
| or | |||
| y | = | 3x - 5 |
Now draw these two graphs:
The lines cross at the point with coordinates (4, 7), so the solution is x = 4, y = 7.Solve the simultaneous equations:
| x + 2y | = | 29 | (1) |
| x + y | = | 18 | (2) |
Note that the equations have been numbered (1) and (2).
Start with equation (2)
| x + y | = | 18 |
| y | = | 18 - x |
Now replace y in equation (1) using y = 18 - x
| x + 2y | = | 29 |
| x + 2(18 - x) | = | 29 |
| x + 36 - 2x | = | 29 |
| 36 - x | = | 29 |
| 36 | = | 29 + x |
| 36 - 29 | = | x |
| x | = | 7 |
Finally, using y = 18 - x gives
| y | = | 18 - 7 |
| y | = | 11 |
So the solution is x = 7, y = 11
Take equation (2) away from equation (1).
| x + 2y | = | 29 | (1) |
| x + y | = | 18 | (2) |
| y | = | 11 | (1) - (2) |
In equation (2), replace y with 11.
| x + 11 | = | 18 |
| x | = | 18 - 11 |
| x | = | 7 |
So the solution is x = 7, y = 11
Solve the simultaneous equations:
| 2x + 3y | = | 28 | (1) |
| x + y | = | 11 | (2) |
From equation (2)
| x + y | = | 11 |
| y | = | 11 - x |
Substitute this into equation (1)
| 2x + 3(11 - x) | = | 28 |
| 2x + 33 - 3x | = | 28 |
| 33 - x | = | 28 |
| 33 | = | 28 + x |
| 33 - 28 | = | x |
| x | = | 5 |
Finally, use y = 11 - x
| y | = | 11 - x |
| y | = | 11 - 5 |
| y | = | 6 |
So the solution is x = 5, y = 6
Subtract 2 × equation (2) from equation (1).
| 2x + 3y | = | 28 | (1) |
| 2x + 2y | = | 22 | 2 × (2) |
| y | = | 6 | (1) - 2 × (2) |
Now replace y in equation (2) with 6.
| x + 6 | = | 11 |
| x | = | 11 - 6 |
| x | = | 5 |
So the solution is x = 5, y = 6
Solve the simultaneous equations:
| x - 2y | = | 8 | (1) |
| 2x + y | = | 21 | (2) |
From equation (2)
| 2x + y | = | 21 |
| y | = | 21 - 2x |
Substitute this into equation (1)
| x - 2y | = | 8 |
| x - 2(21 - 2x) | = | 8 |
| x - 42 + 4x | = | 8 |
| 5x - 42 | = | 8 |
| 5x | = | 8 + 42 |
| 5x | = | 50 |
| x | = | 10 |
Now substitute this into y = 21 - 2x
| y | = | 21 - 2 × 10 |
| y | = | 21 - 20 |
| y | = | 1 |
So the solution is x = 10, y = 1
Subtract 2 × equation (1) from equation (2).
| 2x + y | = | 21 | (2) |
| 2x - 4y | = | 16 | 2 × (1) |
| 5y | = | 5 | (2) - 2 × (1) |
| y | = | 1 |
Now replace this in equation (1).
| x - 2y | = | 8 |
| x | = | 8 + 2 |
| x | = | 10 |
So the solution is x = 10, y = 1