Completing the square is a useful technique for solving quadratic equations. It is a more powerful technique than factorisation because it can be applied to equations that do not factorise.
When completing the square, an expression like,
ax^2 + bx + c is written in the form (Ax + B)^2 + C.
We will begin with the simple example where a = 1. In this case we will write expressions in the form
x^2 + bx + c as (x + B)^2 + C
If we expand (x + B)^2 + C we get x^2 + 2Bx + B^2 + C.
Comparing this with x^2 + bx + c shows that
b = 2B and c = B^2 + C
which gives B = and C = c - B^2
Using these two results we can now set about completing the square in some simple cases.
Write each of the following expressions in the form (x + B)^2 + C.
x^2 + 6x + 1
Comparing x^2 + 6x + 1 with x^2 + bx + c we see that b = 6 and c = 1 in this case, so
B = = = 3 and C = c - B^2 = 1 - 3^2 = -8.
Therefore x^2 + 6x + 1 = (x + 3)^2 - 8.
x^2 + 4x - 2
Here b = 4 and c = –2, so
B = = = 2 and C = c - B^2 = (-2) - 2^2 = -6.
Therefore x^2 + 4x - 2 = (x + 2)^2 - 6.
x^2 + 2x
Here B = = 1 and C = 0 - 1^2 = -1,
so x^2 + 2x = (x + 1)^2 - 1.
Solve the following equations by completing the square.
x^2 - 4x - 5 = 0
Completing the square gives,
x^2 - 4x - 5 = (x - 2)^2 - 9
Now we can solve the equation
| (x – 2)2 | = 9 |
| x – 2 | = ± |
| x – 2 | = ± 3 |
| x | = 2 ± 3 |
| sox | = 5 or –1 |
x^2 + 6x - 1 = 0
Completing the square gives,
x^2 + 6x - 1 = (x + 3)^2 - 10
Now we can solve the equation
| (x + 3)2 | = 10 |
| x + 3 | = ± |
| x | = –3 ± |
| sox | = 0.162 or –6.162 to 3 decimal places |
