In this section we discuss the difference between equations, formulae and identities, and then go on to make use of them.
An equation contains unknown quantities; for example,
3x + 2 = 11
This equation can be solved to determine x.
A formula links one quantity to one or more other quantities; for example,
A = πr2
This formula can be used to determine A for any given value of r.
An identity is something that is always true for any values of the variables that are involved; for example,
If any pair of values of x and y are substituted, then the left hand side of an identity will generate the same value as the right hand side of that identity.
The formula C = (F – 32) is used to convert temperatures in degrees Fahrenheit to degrees Celsius.
If F = 41, calculate C.
C = × (41 – 32)
C = × 9
C = 5
If F = 131, calculate C.
C = × (131 – 32)
C = × 99
C = 55
A formula states that v = u + at.
Calculate v if u = 10, a = 6.2 and t = 20.
When substituting into equations, you need to be aware that the BODMAS rule applies automatically.
v = u + at
v = 10 + 6.2 × 20
v = 10 + 124
v = 134
Solve the following equations:
7x = 21
| 7x = | 21 | |
| x = | Dividing both sides by 7 | |
| x = | 3 |
x – 5 = 12
| x – 5 | = 12 | |
| x | = 12 + 5 | Adding 5 to both sides |
| x | = 17 |
2x + 1 = 6
| 2x + 1 | = 6 | |
| 2x | = 6 – 1 | Subtracting 1 from both sides |
| 2x | = 5 | |
| x | = | Dividing both sides by 2 |
| x | = 2 |
5x – 8 = 22
| 5x – 8 | = 22 | |
| 5x | = 22 + 8 | Adding 8 to both sides |
| 5x | = 30 | |
| x | = | Dividing both sides by 5 |
| x | = 6 |
One of the following statements is not an identity. Which one?
| A | ≡ + | |
|---|---|---|
| B | x - y | ≡ y - x |
| C | x^2 + y^2 | ≡ (x + y)^2 - 2xy |
An identity will be true for any pair of values x and y. We could test each statement with x = 5 and y = 10 .
| Left-hand-side of A | = | = = = 7.5 |
| Right-hand-side of A | = | + = + = 2.5 + 5 = 7.5 |
Therefore LHS of A = RHS of A if x = 5 and y = 10.
| LHS of B | = | x - y = 5 - 10 = -5 |
| RHS of B | = | y - x = 10 - 5 = 5 |
Therefore LHS of B ≠ RHS of B if x = 5 and y = 10.
| LHS of C | = x^2 + y^2 = 5^2 + 10^2 = 25 + 100 = 125 |
| RHS of C | = (x + y)^2 - 2xy = (5 + 10)^2 - 2 × 5 × 10 = 15^2 - 100 |
| = 225 - 100 = 125 |
Therefore LHS of C = RHS of C if x = 5 and y = 10.
So statement B is not an identity. We have not proved that A and C are identities, but we know that they are true for certain values of x and y.