Sometimes we are given an equation with brackets in.
Usually it is best to multiply out the brackets first.
| Solve this equation: | |||
| 5 ( x - 3 ) | = | 35 | |
| Start by multiplying out the brackets: | |||
| 5x - 15 | = | 35 | |
| Now add 15 to both sides: | |||
| 5x | = | 50 | |
| Finally divide by 5 on both sides: | |||
| x | = | 10 | |
|
Gilda thinks of a number and adds 7 to it. She then multiplies her answer by 4 and gets 64. What was her original number?
Start by working out the equation to solve. Let's call Gilda's original number x. |
| 4 ( x + 7 ) | = | 64 | |
| Start by multiplying out the brackets: | |||
| 4x + 28 | = | 64 | |
| Now subtract 28 from both sides: | |||
| 4x | = | 36 | |
| Finally divide by 4 on both sides: | |||
| x | = | 9 | |
| So Gilda's original number was 9. | |||
Practice QuestionsWork out the answer to each of these questions then click on the button marked
(a) Solve the equation: 7(x+3) = 49
(b) James thinks of a number. He subtracts 2 and then multiplies by 5 and gets 45. What was his number?
(c) Look at the rectangle below:
 
ExercisesWork out the answers to the questions below and fill in the boxes. Click on the
Produced by A.J.Reynolds February 2004 | ||||||||||||||||||||||||||||||||||||||||||||||||